Question

At a particular point on Earth, the magnitude of the Earth's magnetic field is 6.50 ✕ 10−5 T. At this point, the field through a small square loop is essentially uniform. The area of the loop is 10.0 cm2. What is the magnitude of the magnetic flux (in T · m2) through the loop when the loop is at the following orientations?

Answer 1

Answer:

The magnitude of the magnetic flux through the loop is 6.5 x 10⁻⁸ T.m²

Explanation:

Given;

Earth's magnetic field, B = 6.50 ✕ 10⁻⁵ T

The area of the small square loop, A = 10.0 cm²

The area of the small square loop in m² = 10.0 cm² x (1 m/100 cm)²

                                                                  = 10.0 cm² x 1 m²/10000 cm²

                                                                  = 0.001 m² = 1 x 10⁻³ m²

Thus, the magnitude of the magnetic flux (in T·m²) through the loop ⇒

Φ = BA

Φ = 6.5 x 10⁻⁵ T x 1 x 10⁻³ m²

Φ =  6.5 x 10⁻⁸ T.m²

Therefore, the magnitude of the magnetic flux (in T·m²) through the loop is 6.5 x 10⁻⁸ T.m²

Answer 2

Answer:

The full solution is given in the picture below

Explanation: