Question

Calculate the pOH of an aqueous solution at 298 K when the hydroxide ion concentration is 3.7 x 10−5 M.

Answer 1

Answer:

pOH = 4.43

Explanation:

pOH = -log[OH⁻] = -log(3.7 x 10⁻⁵) = -(-4.43) = 4.43

Answer 2

The pOH of an aqueous solution = 4.43

Calculation for pOH:

pH is defined by the following equation, pH = −log [H+] ,

where,

[H+] denotes the molar hydrogen ion concentration.

pOH = -log[OH⁻]

pOH= -log(3.7 x 10⁻⁵)

pOH= -(-4.43)

pOH= 4.43

Thus, the pOH of an aqueous solution = 4.43

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