Answer:
The mass of the object is 49.5kg which is approximately 50kg
Explanation:
Given that
Spring constant (k)=45N/m
The extension (e)=0.88m
Also given that the acceleration is 0.8m/s²
Force by the spring is given as
Using hooke's law
According to Hooke's law which states that the extension of an elastic material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically,
F = ke where
F is the applied force
k is the spring constant
e is the extension
From the formula k = F/e
F=ke
m is the mass of the block = ?
a is the acceleration = 0.8m/s²
e is the extension of the spring = 0.88m
k is the spring constant = 45N/m
F=45×0.88
F=39.6N
Now this force will set the object in motion, now using newton second law of motion
F=ma
Then, m=F/a
m=39.6/0.8
m=49.5kg
The mass of the object is 49.5kg which is approximately 50kg
Answer:
Explanation:
Using Hooke's law,
F = -k × delta x
Where,
F = force
k = spring constant
= 45 N/m
Delta x = spring displacement
= 0.88 m
F = 45 × 0.88
= 39.6 N
a = 0.8 m/s^2
Force, F = Mass, M × acceleration, a
M = 39.6/0.8
= 49.5 kg
