A theater group surveyed 146 audience members after a show and found that 132 of them wanted to see the show again. Find the standard error for the sample proportion of audience members for that show who want to see the show again. Enter your answer as a decimal rounded to three decimal places.

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Answer:

0.024

Step-by-step explanation:

Sample size (n) = 146 people

The proportion (p) of people who answered that they would be interested in seeing the show again is:

[tex]p=\frac{132}{146}\\ p=0.9041[/tex]

The standard error for a sample of size 'n' and proportion 'p' is:

[tex]SE = \sqrt{\frac{p*(1-p)}{n}}\\SE = \sqrt{\frac{0.9041*(1-0.9041)}{146}}\\ SE=0.024[/tex]

The standard error for the sample proportion of audience members who want to see the show again is 0.024.

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