Question

what are the factors in the expression 4x(3x^2+5y)?

Answer 1

4x(3x²+5y) expand by distributing terms

4x*3x²+4x*5y take out the constants

(4*3)xx²+4x*5y simplify 4*3 to 12

12xx²+4x*5y use product rule=xᵃxᵇ=xᵃ+ᵇ, and change the two variables (the x's) into ones, because if there is just one variable with no number by it, then it is a one.

12x¹⁺²+4x*5y and simplify 1+2 to 3.

12x³+4x*5y finally simplify 4x*5y to 20xy

12x³+20xy

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Answer 2

The factors in the expression $4x(3x^2+5y)$ are $12x^3+20xy.$

What is factorization?

In mathematics, factorization or factoring consists of writing a number or another mathematical object as a product of several factors.

$=4x(3x^2+5y)$

$=(4x\times 3x^2+4x\times 5y)$

$=(12x^3+20xy)$

Hence factors in the expression 4x(3x^2+5y are 12x³+20xy.

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