Answer:
0.7755
Step-by-step explanation:
If 120 CDs are defective, the number of non-defective CDs in the batch is:
[tex]n=1950-120\\n=1830[/tex]
In order for the batch to be accepted, all of the 4 CDs in the sample must not be defective, the probability of that happening is:
[tex]P=\frac{1830}{1950}*\frac{1829}{1949} *\frac{1828}{1948} *\frac{1827}{1947}\\P=0.7755[/tex]
The probability that the entire batch will be accepted is 0.7755.