A runaway train car that has a mass of 1.550×104kg travels at a speed of 5.35m/s down a track. Compute the time required for a force of 1.50×103N to bring the car to rest.

Respuesta :

Answer:

55.15 sec.

Explanation:

Given that the force = [tex]1.50\times 10^3[/tex] N

We know, Force = mass × acceleration

So,

Acceleration = [tex]\frac{Force}{Mass}= \frac{1.50\times10^3}{1.550\times10^4} = 0.097 ms^-^2[/tex] is the negative acceleration produced by the force.

Now, using formula [tex]v=u-at[/tex]

As the car finally stops so [tex]v[/tex] will be zero.

So,

[tex]0=5.35-0.097\times t[/tex]

Thus, [tex]t= \frac{5.35}{0.097}[/tex] = 55.15 sec.

So, the time required for the force to bring the car to rest will be 55.15 seconds.

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