Question

A 15.0 kg medicine ball is thrown at a velocity of 10.0 m/s to a 60.0 kg person who is a rest on ice. The person catches the ball and immediately slides across the ice. Assume that momentum is conserved and there is no friction. Calculate the velocity of the person AND THE BALL.

Answer 1

Answer:

Ball = 150kg*m/s

Explanation:

How to find momentum, p:

p = m*v    (P=MOMENTUM, M=MASS, V=VELOCITY OF BALL)

P = 15*10

P=150

For the human, momentum is always conserved, so what the momentum is before the ball is thrown must equal after the ball is thrown:

pBEFORE= pAFTER

mv = mv

(15)(10) = (60)(v)    SOLVE FOR V

150 = 60v

v = 5/3

Answer 2

The velocity of the person is required.

The velocity of the person is 2 m/s.

$m_1$ = Mass of medicine ball = 15 kg

$v_1$ = Velocity of medicine ball = 10 m/s

$m_2$ = Mass of person = 60 kg

v = Velocity of the person and the ball

As the momentum is conserved we have

$m_1v_1=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1v_1}{m_1+m_2}\\\Rightarrow v=\dfrac{15\times 10}{60+15}\\\Rightarrow v=2\ \text{m/s}$

The velocity of the person and the ball is 2 m/s.

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