Question

Calculate the molarity of 0.289 moles of FeCl3 dissolved in 120 ml of solution?

Answer 1

Answer:

The molarity is 2,408M

Explanation:

A solution molar---> moles of solute in 1 L of solution (1000ml):

120ml solution --------0,289 mol FeCl3

1000ml solution-------x= (1000ml solutionx0,289 mol FeCl3)/120 ml solution

x=2,408mol FeCl3--> 2, 408M

Answer 2

The molarity of the solution is the ratio of the moles and the volume of the solution in which it is present. The molarity of $\rm FeCl_{3}$ is 2.408 M.

What is molarity?

Molarity is the estimation of the molar concentration of the species dissolved in the volume of the solution.

The molarity can be calculated as:

$\rm Molarity = \dfrac{moles}{Volume}$

Given,

Moles (n) of Iron(III) chloride = 0.289 moles

Volume of the solution = 120 mL

Substituting values in the equation above:

$\begin{aligned}\rm M&= \dfrac{0.289\times 1000}{120}\\\\&= 2.480\;\rm M\end{aligned}$

Therefore, 2.480 M is the molar concentration of Iron(III) chloride solute.

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