Answer: The standard entropy of vaporization of ethanol is 0.275 J/K
Explanation:
[tex]C_2H_5OH(l)\rightleftharpoons C_2H_5OH(g)[/tex]
Using Gibbs Helmholtz equation:
[tex]\Delta G=\Delta H-T\Delta S[/tex]
For a phase change, the reaction remains in equilibrium, thus [tex]\Delta G=0[/tex]
[tex]\Delta H=T\Delta S[/tex]
Given: Temperature = 285.0 K
[tex]\Delta H=78.3J/mol[/tex]
Putting the values in the equation:
[tex]78.3J=285.0K\times \Delta S[/tex]
[tex]\Delta S=0.275J/K[/tex]
Thus the standard entropy of vaporization of ethanol is 0.275 J/K