Question

In Case 1, a force F is pushing perpendicular on an object a distance L/2 from the rotation axis. In Case 2 the same force is pushing at an angle of 30 degrees a distance L from the axis.

In which case is the torque due to the force about the rotation axis biggest?
A. Case 1
B. Case 2
C. Same

Answer 1

Answer:

Explanation:

In case 1 , torque due to force acting at distance L/2

torque = Force x perpendicular distance from axis

= F X L / 2

= FL /2

In the second case, perpendicular component of force

= F Sin30 .

= F / 2

Torque

= Force x perpendicular distance from axis

= L X F / 2

So they are same ,