Question

The drop-counter is misaligned with the buret, causing it to miss counting every one out of five drops of base added to the HCl. This error means the calculated molarity of the HCl solution will be ___________ its actual concentration.

Answer 1

Answer:

Less than

Explanation:

According to the question, the drop counter is counting four out of five drops of base added to the HCl. So when the titration will reach to the end point the volume of Base recorded will be less than the actual volume of the base dropped in the solution.

We will use law of equivalence for the calculation of concentration of HCl,

$M_1V_1 = M_2V_2$

Where, $M_1$ and $V_1$ are molarity and volume of HCl and $M_2$ and $V_2$ are molarity of volume of the base added.

Thus concentration of HCl will be calculated as,

$M_1=\frac{M_2V_2}{V_1}$

As the recorded $V_2$ is less than the actual amount present in the solution, the calculated value of concentration of HCl will also be less than the actual.

Answer 2

This error means the calculated molarity of the HCl solution will be less than its actual concentration.

From the information given, we are informed that the drop-counter is misaligned with the buret, which leads it to miss counting every one out of five drops of base added to the HCl.

Due to this, when the titration reaches the endpoint, then the volume of the base that's recorded will be less than the actual volume of the base that was dropped in the solution.

In conclusion, as it misses one drop of base for five drops of the added base, it'll lead to a scenario where the volume of base calculated will be less than the actual volume.

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