When the current through a circular loop is 4.20 A, the magnetic field at its center is 5.21\times 10^{-4}~\text{T}5.21×10 ​−4 ​​ T. What is the radius of the loop?

Respuesta :

Answer:

Radius of the loop = [tex]5.065\times 10^{-3} m[/tex]

Explanation:

The magnetic field at the center of a circle is given by the formula

[tex]B= \frac{\mu I}{2B}\\\\[/tex]

where I current = 4.2A

Magnetic Field , B = [tex]5.21\times 10^{-4}[/tex]T

[tex]\mu[/tex] = [tex]4\pi\times 10^{-7}\times 4.2 H/m[/tex] ( permeability)

plugging in the parameters and evaluating, we have

[tex]\frac{4\times\pi\times10^{-7}\times 4.2 }{2\times5.21\times10^{-4} }[/tex]

= [tex]=5.065\times 10^{-3}[/tex]

The radius of the  loop = [tex]5.065\times 10^{-3} m[/tex]

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