[tex]\huge\boxed{a=\frac{229}{2};\ \ b=\frac{51}{2}}[/tex]
In decimal form, a = 114.5; b = 25.5
We will write this as a system of equations, where [tex]a[/tex] and [tex]b[/tex] are the two angles.
[tex]\left \{ {{a=5b-13} \atop {a+b=140}} \right[/tex]
We will use substitution to solve this system. We know what [tex]a[/tex] equals, so we plug that into the second equation.
[tex]5b-13+b=140[/tex]
Combine the like terms.
[tex]6b-13=140[/tex]
Add [tex]13[/tex] on both sides.
[tex]6b=153[/tex]
Divide both sides by [tex]6[/tex].
[tex]b=\frac{153}{6}=\boxed{\frac{51}{2}}[/tex]
Now just subtract that from [tex]140[/tex].
[tex]a=140-\frac{51}{2}=\boxed{\frac{229}{2}}[/tex]