Question

You are standing on a concrete slab that in turn is resting on a frozen lake. Assume there is no friction between the slab and the ice. The slab has a weight five times your weight. If you begin walking forward at 2.00 m/s relative to the ice, with what speed, relative to the ice, does the slab move?

Answer 1

Answer:

Explanation:

Let the speed of slab with respect to ice be v

We shall apply law of conservation of momentum as movement to both slab and myself has emerged due to internal forces

( friction )

2 x m = v x 5 m   ( m and 5m are masses of man and slab )

v =2/5  m/s

velocity of slab wrt  to ice is 2/5 m /s

Answer 2

The velocity of slab with respect to ice is $\frac{2}{5} m/s$.

Law of conservation of momentum:

The momentum is always conserved.

Let us consider that mass of man is $m$

• Since, The slab has a weight five times of man weight.

• So that, mass of slab is $5m$.

Assume that velocity of slab with respect to ice is $v$

             $2*m=v*5m\\\\5v=2\\\\v=\frac{2}{5} m/s$

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