On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population gains 87\%87%87, percent of its size every 2.42.42, point, 4 days, and can be modeled by a function, LLL, which depends on the amount of time, ttt (in days).
Before the first day of spring, there were 1100 locusts in the population.

The population of locusts changes exponentially. Initially, there are 1100 locusts. Every 2.4 days, the population increases by 87%. So the equation L(t) is:

L(t) = 1100 (1.87)^(t/2.4)

After 1 day, the population is:

L(1) = 1100 (1.87)^(1/2.4)

L(1) = 1428

Compared to the initial 1100, the population increases by a factor of:

1428 / 1100 = 1.30

Since the daily rate of change is greater than 1, the population grows.

shivishivangi1679 shivishivangi1679 · Answer 2 · 2022-07-30T12:31:27+02:00

Every day, the locust population grows by a factor of 1.30.

What is a system of equations?

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

The population of locusts changes exponentially and Initially, there are 1100 locusts.

Every 2.4 days, the population increases by 87%,

The equation L(t) is:

L(t) = 1100 (1.87)^(t/2.4)

After 1 day, the population is:

L(1) = 1100 (1.87)^(1/2.4)

L(1) = 1428

Now, Compared to the initial 1100, the population increases by a factor of:

1428 / 1100 = 1.30

Therefore, the daily rate of change is greater than 1, the population grows.

Learn more about equations here;

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