Question

A small but heavy lead weight is attached to a lightweight string with a length of 0.55 m. Determine the natural period of the lead weight if it oscillates with a small amplitude on the end of the string.

Answer 1

Answer:

The natural period is 1.49 s

Explanation:

T = 2πsqrt(L/g)

T is the natural period

π = 3.142

L is length of the string = 0.55 m

g is acceleration due to gravity = 9.8 m/s^2

T = 2×3.142sqrt(0.55/9.8) = 6.284sqrt(0.05612) = 6.284×0.237 = 1.49 s