Answer:
13.8 W/m^2 °C
Explanation:
At average surface temperature, the dynamic viscosity of air is
[tex]\mu_s=\mu_{at 25^0C} = 2.76 10^{-5} kg/ms\\\\[/tex]
The properties of air at temperature of 27°C and 1 ATM are:
k = 0.02551 W/m · °C
V= 1.562 x 10⁵ m²/s
μ= 1.849 x 10⁵ kg/ms
Pr = 0.7296
Reynolds number⇒
[tex]Re=\frac{VD}{v} =\frac{(3 \ m/s)(0.25 \ m)}{1.562 \times 10^5 m^2/s} = 4.802 \times 10^4\\[/tex]
Nusselt number ⇒
[tex]Nu = \frac{hD}{k} = 2 + [0.4Re^{1/2}+0.06Re^{2/3}]Pr^{0.4}(\frac{\mu_{\infty}}{\mu_s} )\\\\= 2 + [0.4(4.802 \times 10^4)^{1/2}+0.06(4.802 \times 10^4)^{2/3}](0.7296)^{0.4}(\frac{1.849 \times 10^{-5}}{2.76 \times10^5 } )\\\\=135[/tex]
The convection heat transfer co efficient is
[tex]h=\frac{k \times Nu}{D} =\frac{0.02551\times135}{0.25} \\\\= 13.8 W/m^2 .^oC[/tex]