Answer:
a. P(both stat)=0,36
b. P(both math)=0,16
c. P( at least one sstatt)=0,84
d. P( at least on smath)=0,64
Step-by-step explanation:
Number of students= 5
Number of students math majors=2
Number of students statistics majors=3
a. Probability that both selected students are statistics majors
P(x)=3/5*3/5=0,36
b. Probability that both students are math majors
P(x)=2/5*2/5=0,16
c. Probability that at least one of the students selected is a statistics major
P(sstat)=3/5=0,6
P(not sstat)=2/5=0.4
P(sstat)=1-P(not sstat)∧n
P( at least on sstat)=1-0.4∧2=0.84
d. Probability that the selected students have different majors
P(smath)=2/5=0,4
P(not smath=2/5=0.6
P(smath)=1-P(not smath)∧n
P( at least on smath)=1-0.6∧2=0.64