Answer:
The temperature of propane in the flask was 788.9 K or 515.75 °C
Explanation:
Step 1: Data given
Volume of the flask = 2.50 L
Mass of propane = 1.65 grams
Molar mass of propane = 44.1 g/mol
Pressure = 736 mmHg = 0.968421 atm
Step 2: Calculate moles propane
Moles propane = mass propane / molar mass propane
Moles propane = 1.65 grams / 44.1 g/mol
Moles propane = 0.0374 moles
Step 3: Calculate temperature
p*V = n*R*T
T = (p*V)/(n*R)
⇒with T = the temperature in the flask
⇒with p = the pressure of propane gas = 0.968421 atm
⇒with V = the volume of the flask = 2.50 L
⇒with n = the number of moles propane gas = 0.0374 moles
⇒with R = the gas constant = 0.08206 L*atm/mol*K
T = (0.968421 * 2.50)/(0.0374*0.08206)
T = 788.9 K
The temperature of propane in the flask was 788.9 K or 515.75 °C
Answer:
788.6K
Explanation:
First, let us calculate the number of mole propane(C3H8). This can be achieved as shown below:
Molar Mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44g/mol
Mass of C3H8 obtained from the question = 1.65g
Number of mole = Mass /Molar Mass
Number of mole of C3H8 = 1.65/44 = 0.0375mol
Now we can obtain the temperature of propane gas as shown below:
V = 2.50L
P = 736mmHg
Recall that 760mmHg = 1atm
Therefore 736mmHg = 736/760 = 0.97atm
n = 0.0375mol
R = 0.082atm.L/Kmol
T =?
PV = nRT
T = PV/nR
T = 0.97x 2.5 / 0.0375x0.082
T = 788.6K
The temperature of the propane was 788.6K
