Question

write (1/13)^2=1/169 in logarithmic form

Answer 1

Answer:

  $\log_{1/13}(1/169)=2$

Step-by-step explanation:

The exponential expression b^a=c is equivalent to the log expression ...

  $\log_b{(c)}=a$

Filling in a=2, b=1/13, c=1/169 you get the logarithmic form ...

  $\boxed{\log_{1/13}(1/169)=2}$