Question

Anthony and Maria mix two liquids, ethylene glycol and water, to create a coolant for their car. Find the volume (mL) for a 12.9 lbm mixture with 0.593 mass fraction of ethylene glycol and the remaining water.

Answer 1

Answer:

$V=5545.2mL$

Explanation:

Hello,

In this case, by considering the mass fractions and the solution's mass, one computes both ethylene glycol's and water's masses:

$m_{etg}=12.9lbm*0.593=7.64lbm\\m_{H_2O}=12.9lbm-7.64lbm=5.26lbm$

Now, the densities are considered to find the volume of the solution as shown below:

$V=V_{etg}+V_{H_2O}\\V=7.64lbm*\frac{1ft^3}{68.5lbm} +5.26lbm*\frac{1ft^3}{62.4lbm} \\V=0.196ft^3*\frac{28316.8mL}{1ft^3} \\V=5545.2mL$

Best regards.