Calculate the value of D at 575°C for the diffusion of some species in a metal for which the values of D0 and Qd are 4.5 × 10-5 m2/s and 160 kJ/mol, respectively.

Respuesta :

Answer:

The value of D = 4.4 × [tex]10^{-5}[/tex]

Explanation:

Temperature T = 575 °c = 848 K

[tex]D_{0}[/tex] = 4.5 × [tex]10^{-5}[/tex] [tex]\frac{m^{2} }{sec}[/tex]

[tex]Q_{d}[/tex] = 160 [tex]\frac{KJ}{mol}[/tex]

The value of [tex]D_{0}[/tex] is given by the formula

[tex]D_{0}[/tex] = D exp   [tex]( \frac{Q_{d} }{RT} )[/tex]

Put all the values in above formula we get,

4.5 × [tex]10^{-5}[/tex] = D exp [tex]\frac{160}{7050.272}[/tex]

4.5 × [tex]10^{-5}[/tex] = D × 1.023

D = 4.4 × [tex]10^{-5}[/tex]

This is the value of D.