Respuesta :
Answer:
Therefore the height of the tower is 101.79 m.
Step-by-step explanation:
The ratio of the height of an object to the shadow of the object is always constant at certain time.
[tex]\frac{\textrm{The height of object}}{\textrm{The shadow of the object}}= constant[/tex]
[tex]\Rightarrow \frac{h_1}{s_1}=\frac{h_2}{s_2}[/tex]
Given that,the length of the pole is 3.5 m and it casts a shadow that is 1.47 m long.
The length of shadow that castes by a tower is 42.75 m long.
Here h₁= 3.5 m, s₁=1.47 m, h₂= ? and s₂=42.75 m
[tex]\therefore \frac {3.5}{1.47}=\frac{h_2}{42.75}[/tex]
⇒3.5 ×42.75 = h₂× 1.47
[tex]\Rightarrow h_2=\frac{3.5 \times 42.75}{1.47}[/tex]
⇒h₂ = 101.79 m (approx)
Therefore the height of the tower is 101.79 m.
