Answer:
0.20M
Explanation:
First let us generate a balanced equation for the reaction. This is illustrated below:
H2SO4 + 2LiOH —> Li2SO4 + 2H2O
From the equation above,
nA (mole of the acid) = 1
nB (mole of the base) = 2
Data obtained from the question include:
Ma =?
Va = 25.0mL
Mb = 0.12 M
Vb = 83.6 mL
The concentration of the acid can be obtain as follows:
MaVa/MbVb = nA/nB
Ma x 25/ 0.12 x 83.6 = 1/2
Cross multiply to express in linear form as shown below:
Ma x 25 x 2 = 0.12 x 83.6
Ma x 50 = 10.032
Divide both side by 50
Ma = 10.032/50
Ma = 0.20M
The concentration of the acid is 0.20M