Question

​A 460-turn solenoid of length 30.0 cm and radius 4.00 cm carries a current of 3.50 A. What is the magnetic field strength inside the coil at its midpoint? What is the magnetic field strength inside the coil at its midpoint?

Answer 1

Answer:

Magnetic field at the mid point of coil is 6.74 x 10⁻³ T

Explanation:

Given :

Current flowing through the solenoid, I = 3.50 A

Length of the solenoid, L = 30 cm = 0.3 m

Number of turns in the solenoid, N = 460

Magnetic field inside the coil at its mid point is given by the relation:

B = μ₀nI    ...(1)

So, equation (1) becomes:

$B=\mu_{0}\frac {N}{L}I$

Substitute the suitable values in the above equation.

$B=4\pi\times10^{-7}\times \frac {460}{0.3}\times3.50$

B = 6.74 x 10⁻³ T