Question

Calculate the heat absorbed by
105.0 kilograms of water when it is
heated to cook spaghetti. The
initial temperature of the water is
20.0°C, and the final temperature
of the water is 99.0°C. The specific
heat of water is 4.18 J/kg•°C.

Answer 1

Answer:

Heat required to heat the given amount of water is

$Q = 3.47 \times 10^7 J$

Explanation:

As we know that heat required to raise the temperature of water is given as

$Q = ms\Delta T$

here we have

m = 105 kg

s = 4180 J/kg C

now we have

$\Delta T = 99 - 20$

now we have

$Q = 105 (4180)(99 - 20)$

$Q = 3.47 \times 10^7 J$