Question

A balloon contains 0.692 mil of ammonia gas, NH3(g), at 280 K and a pressure of 0.810 bar. What is the volume in liters of the balloons?

Answer 1

Answer:

$\large \boxed{\text{19.9 L}}$  

Explanation:

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.810 bar

n = 0.690 mol

T = 280 K

Calculation:

$\begin{array}{rcl}\text{0.810 bar} \times V & = & \text{0.692 mol} \times \text{0.083 14 bar}\cdot\text{L}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{280 K}\\0.810V & = & \text{16.11 L}\\V & = & \textbf{19.9 L} \\\end{array}\\\text{The volume of the balloon is \large \boxed{\textbf{19.9 L}} }$

Answer 2

Answer

I checked the answer with Kahn Academy and it is correct, so the answer is --> 19.9