How quickly must a 56.7−g tennis ball travel in order to have a de Broglie wavelength that is equal to that of a photon of green light (5.40 × 103 Å)? Enter your answer in scientific notation.

Respuesta :

Answer:

v = 2.2 * 10^(-24) m/s

Explanation:

Momentum is given in terms of wavelength as:

p = h/λ

Where h is Planck's constant = 6.626 * 10^(-34) kgm²/s

Hence, momentum will be:

p = 6.626 * 10^(-34) / (5.4 * 10^3 * 10^(-10)

p = 1.23 * 10^(-27) kgm/s

For a 56.7 g ball to have the same wavelength as green light, they must have the same momentum.

Momentum is given in terms of mass as:

p = m*v

p = 0.0567 * v

1.23 * 10^(-27) = 0.0567 * v

v = 1.23 * 10^(-27) / 0.0567

v = 2.2 * 10^(-24) m/s

Hence, it would have to move at a speed of 2.2 * 10^(-24) m/s to have the same wavelength.

Answer:

The tennis ball has a speed of [tex]2.16x10^{-26}m/s[/tex] in order to have that wavelength.  

Explanation:

The wavelength of the electron can be determined by means of the de Broglie equation.

[tex]\lambda = \frac{h}{p}[/tex] (1)

                       

Where h is the Planck's constant and p is the momentum

[tex]\lambda = \frac{h}{mv}[/tex] (2)

Therefore, v can be isolated from equation 2

[tex]v = \frac{h}{m\lambda}[/tex]                

Notice that it is necessary to express the wavelength in units of meters and the mass in units of kilograms.

[tex]\lambda = 5.40x10^{3}Å .\frac{1x10^{-10}m}{1Å}[/tex] ⇒ [tex]5.4x10^{-7}m[/tex]      

[tex]m = 56.7g .\frac{1Kg}{1000g}[/tex] ⇒ [tex]0.0567Kg[/tex]    

     

[tex]v = \frac{6.624x10^{-34} J.s}{(0.0567Kg)(5.4x10^{-7}m)}[/tex]

                                   

But [tex]1J = Kg.m^{2}/s^{2}[/tex]    

     

[tex]v = \frac{6.624x10^{-34} Kg.m^{2}/s^{2}.s}{(0.0567Kg)(5.4x10^{-7}m)}[/tex]

                 

[tex]v = 2.16x10^{-26}m/s[/tex]        

Hence, the tennis ball has a speed of [tex]2.16x10^{-26}m/s[/tex] in order to have that wavelength.  

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