Respuesta :
Answer:
The number of moles present in the container N = 81.56
Explanation:
Pressure = 1 atm = 101325 K pa
Temperature = 298 K
Volume = 0.002 [tex]m^{3}[/tex]
Gas constant for oxygen = [tex]\frac{8.314}{32}[/tex] = 0.26 [tex]\frac{KJ}{Kg K}[/tex]
From ideal gas equation
P V = m R T -------- (1)
Put all the values in above formula,
101325 × 0.002 = m × 0.26 × 298
⇒ m = 2.61 kg= 2610 gm
This is the mass of the gas.
Now no. of moles of the gas is calculated by
[tex]Number of moles = \frac{Mass of substance}{Mass of one mole}[/tex]
[tex]N = \frac{m}{M}[/tex]
Mass of one mole of oxygen = 32 gm
N = [tex]\frac{2610}{32}[/tex]
N = 81.56
These are the number of moles present in the container.
The number of moles of the air is 0.08 moles.
Using the ideal gas law;
PV = nRT
P = pressure
V = volume
n = Number of moles
R = gas constant
T = temperature in Kelvin
The values are as follows;
P = 1 atm
T = 25∘C + 273 = 298 K
n = ?
R = 0.082 atmLK-1mol-1
V = 2 L
n = PV/RT
n = 1 atm × 2 L/0.082 atmLK-1mol-1 × 298 K
n = 0.08 moles
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