Question

Radiation emitted from human skin reaches its peak at λ = 940 µm. (a) What is the frequency of this radiation? (b) What type of electromagnetic waves are these? (c) How much energy (in electron volts) is carried by one quantum of this radiation?

Answer 1

Answer:

a) the frequency is 3.191x10^11

b)the radiation is a microwave radiation

c) the energy of one quantum of this radiation is 1.32x10^-3ev

Explanation:

Detailed explanation and calculation is shown in the image below

Answer 2

The radiation emitted by human skin :

(a) has a frequency of 3.2×10¹¹ Hz

(b) belong to the category of microwaves

(c) contains 1.325 meV energy in one quantum

Radiation emitted by human skin:

Given that the radiation emitted from human skin has a peak wavelength of λ = 940 µm

(a) The relation between frequency (f) and wavelength of an electromagnetic wave is given by:

f = c/λ

where c is the speed of light

f = 3×10⁸/940×10⁻⁶

f = 3.2×10¹¹ Hz

(b) The given electromagnetic wave belongs to the category of microwaves which have frequencies ranging from 10⁸ Hz to 10¹² Hz

(c) The energy carried by one quantum is given by:

E = hf

E = 6.626×10⁻³⁴×3.2×10¹¹ J

E = 21.20×10⁻²³J

converting it to eV:

E = 21.20×10⁻²³/1.6×10⁻¹⁹

E = 1.325×10⁻³eV

Learn more about microwave radiations:

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