Question

Heat is flowing through a slab of material by conduction heat transfer; and the heat flux is 16500W/m^2. If the slab is 3.0 cm thick and the thermal conductivity is 18 W /(m K), what is the temperature difference across the slab?

Answer 1

Answer:

The temperature difference across the slab is 27.5 K.

Explanation:

Q/A = k∆T/t

Q/A is heat flux = 16,500 W/m^2

k is thermal conductivity = 18 W/m.K

∆T is temperature difference

t is thickness of the slab = 3 cm = 3/100 = 0.03 m

∆T = (heat flux × thickness)/thermal conductivity = 16,500×0.03/18 = 27.5 K