Answer: [tex]x = -3[/tex] and [tex]y = 4[/tex]
Step-by-step explanation:
[tex]2x+5y = 14[/tex] ....................... equation 1
[tex]6x+7y = 10[/tex] ....................... equation 2
Using elimination method
multiply equation 1 by (3) and equation 2 by (1)
Then we have:
[tex]6x + 15y = 42[/tex] .................. equation 3
[tex]6x + 7y = 10[/tex] ................... equation 4
subtract equation 4 from equation 3 , we have
[tex]8y = 32[/tex]
divide through by 8
[tex]y = 4[/tex]
substitute [tex]y = 4[/tex] into equation 1 to get the value of x
that is :
[tex]2x + 5(4) = 14[/tex]
[tex]2x + 20 = 14[/tex]
[tex]2x = 14 - 20[/tex]
[tex]2x = -6[/tex]
[tex]x = -3[/tex]
Therefore:
[tex]x = -3[/tex] and [tex]y = 4[/tex]
