Answer:
The answer to your question is 576 grams of FeO
Explanation:
Balanced chemical reaction
2Fe + O₂ ⇒ 2 FeO
Reactant Elements Products
2 Fe 2
2 O 2
Data
mass of FeO = ?
moles of Fe = 8
Excess Oxygen
Process
1.- Convert moles of Fe to grams
Atomic mass = 56 g
56 g of Fe ------------------ 1 mol
x ------------------ 8 moles
x = (8 x 56) / 1
x = 448 g of Fe
2.- Use the coefficients of the balanced reaction to find the grams of FeO.
Molecular mass of FeO = 2[ 56 + 16]
= 144 g
2(56) g of Fe ----------------------- 144 g of FeO
448 g ----------------------- x
x = (448 x 144) / 2(56)
x = 64512 / 112
x = 576 grams of FeO
