The solution of the equation is [tex](\frac{-5 - \sqrt{33}}{2}, \frac{-5 + \sqrt{33}}{2})[/tex]
How to determine the solutions?
The equation is given as:
x ^ 2 = - 5x + 8
Rewrite as:
x^2 + 5x - 8 = 0
The above equation is a quadratic equation with the following parameters:
a = 1, b= 5 and c = -8
The solution is calculated as:
[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
So, we have:
[tex]x = \frac{-5 \pm \sqrt{(1)^2 - 4 * 1 * -8}}{2 * 1}[/tex]
Evaluate
[tex]x = \frac{-5 \pm \sqrt{33}}{2}[/tex]
Split
[tex]x = (\frac{-5 - \sqrt{33}}{2}, \frac{-5 + \sqrt{33}}{2})[/tex]
Hence, the solution of the equation is [tex](\frac{-5 - \sqrt{33}}{2}, \frac{-5 + \sqrt{33}}{2})[/tex]
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