Jason takes off from rest across level water on his jet-powered skis. The combined mass of Jason and his skis is 75 kg (the mass of the fuel is negligible). The skis have a thrust of 200 N and a coefficient of kinetic friction on water of 0.10. Unfortunately, the skis run out of fuel after only 16 s. What is Jason's top speed

Respuesta :

Answer:

27.04 m/s

Explanation:

We are given that

Total mass,M=75 kg

Thrust force=F=200 N

Coefficient of friction, [tex]\mu=0.1[/tex]

Time,t=16 s

We have to find the Jason's top speed.

Net force,F=Ma=Thrust-Friction

[tex]75a=200-\mu mg=200-0.1\times 9.8\times 75=126.5[/tex]

Where [tex]\mu=0.1,g=9.8 m/s^2[/tex]

[tex]a=\frac{126.5}{75}[/tex]

[tex]a=1.69 m/s^2[/tex]

We know that

[tex]a=\frac{v-u}{t}[/tex]

[tex]u=0[/tex]

Substitute the  values

[tex]1.69=\frac{v-0}{16}[/tex]

[tex]v=1.69\times 16=27.04 m/s[/tex]

Hence, Jason's top speed=27.04 m/s

Answer:

Explanation:

initial velocity, u = 0 m/s

mass, m = 75 kg

Thrust, F = 200 N

coefficient of kinetic friction, μk = 0.1

time, t = 16 s

Let a be the acceleration.

by Newton's second law

ma = F - friction force

ma = 200 - 0.1 x 75 x 9.8

75 a = 200 - 73.5

75 a = 126.5

a = 1.69 m/s²

By first equation of motion

v = u + at

v = 0 + 1.69 x 16

v = 27.14 m/s  

ACCESS MORE