Give the formula of each of the following (don't worry about subscripts or superscripts, example: HCO3- enter as HCO3-): the conjugate acid of HSO3- H2SO3 the conjugate base of H2O the conjugate acid of NH3 the conjugate base of CH3NH2

In a Brønsted-Lowry acid-base reaction, a conjugate acid is the species resulting from a base accepting a proton; likewise, a conjugate base is the species formed after an acid has donated a hydrogen atom (proton).

To this end:

HSO3- is the conjugate acid of H2SO3 i.e sulfuric acid has lost a proton (H+)
NH4+ is the conjugate acid of NH3 i.e the base ammonia has gained a proton (H+)
OH- is the conjugate base of H20
CH3NH3+ is the conjugate base of the base CH3NH2 methylamine

joetheelite joetheelite · Answer 2 · 2020-03-24T02:09:14+01:00

Answer:

See explanation below

Explanation:

In this case, for you to understand, let's do the acid base reaction, so you can see the conjugate base or acid.

For the case of the HSO3-, if you do the reaction:

HSO3- + H2O ------> H2SO3 + OH-

In this case, the negative charge, acts as a base, and took an hydrogen from the water. This forms the OH- and the conjugate acid of the HSO3-. The H2SO3 is called sulfurous acid.

For the case of H2SO3:

H2SO3 + H2O ---------> HSO3- + H3O+

The H2SO3 acts like acid, so the conjugate base would be the HSO3-

For the H2O:

2H2O --------> H3O+ + OH-

The water acts as base and acid at a time. In this case, when it acts like a base, took one hydrogen atom from the other molecule of water, and forms the H3O+. This would be the conjugate acid. The conjugate base would be the OH-

For the NH3:

NH3 + H2O --------> NH4+ + OH-

The atom of nitrogen in the NH3, took an atom of hydrogen to form the NH4+, which would be the conjugate acid.

For the CH3NH2:

CH3NH2 + H2O -------> CH3NH- + H3O+

The water took an atom of hydrogen, so, the water is the base and CH3NH2 is the acid, so the conjugate base is the CH3NH-

Regards