Answer:
B, i think.
Explanation:
Calculate the number of moles of solute present.
Moles of Na0H =15.0g Na0H x 1 molNa0H over 40.00g Na0H= 0.375 mol Na0H.
Calculate the liters of solution present.
volume=225mL x iL over 1000mL = 0.225 L soln
Divide the number of moles of solute by the number of liters of solution.
Molarity= 0.375mol over 0.225L =1.67 mol/L