Question

At an amusement park, the probability that a child eats popcorn and cotton candy is 0.58. The probability that a child eats popcorn is 0.69 and the probability that a child eats cotton candy is 0.87. What is the probability (rounded to the nearest hundredth) that a child eats cotton candy given that the child has already eaten popcorn

Answer 1

Answer:

0.84 is the required probability.

Step-by-step explanation:

We are given the following in the question:

Probability that a child eats popcorn and cotton candy = 0.58

$P(p\cap c) = 0.58$

Probability that a child eats popcorn = 0.69

$P(p) = 0.69$

Probability that a child eats cotton candy = 0.87

$P(c) = 0.87$

We have to evaluate the conditional probability that a child eats cotton candy given that the child has already eaten popcorn.

$P(c|p)\\\\=\dfrac{P(c\cap p)}{P(p)}\\\\=\dfrac{0.58}{0.69}\\\\=0.84$

0.84 is the probability that a child eats cotton candy given that the child has already eaten popcorn.