Step-by-step explanation:
Here, the given question is incomplete .
A math class has 4 girls and 4 boys in the seventh grade and 7 girls and 5 boys in the eighth grade. The teacher randomly selects a seventh grader and an eighth grader from the class for a competition. What is the probability that the students she selects are both boys?
Solving the given question we get:
The total number of girls in the 7th grade = 4
The total number of boys in the 7th grade = 4
So, the probability of selecting a boy in 7th grade = [tex]\frac{\textrm{Total number of boys}}{total students in 7th grade} = \frac{4}{4+4} = \frac{1}{2}[/tex] .... (1)
The total number of girls in the 8th grade = 7
The total number of boys in the 8th grade = 5
So, the probability of selecting a boy in 8th grade = [tex]\frac{\textrm{Total number of boys}}{total students in 8th grade} = \frac{5}{5+7} = \frac{5}{12}[/tex] .... (2)
Now, combination of both the probabilities, we get:
The probability that both students selected are boys = [tex]\frac{1}{2} \times \frac{5}{12} = \frac{5}{24}[/tex]
Hence, probability of randomly selecting both students as boys is [tex](\frac{5}{24})[/tex]