Answer:
[tex]\Delta _rG=2832.2J/mol[/tex]
Explanation:
Hello,
In this case, the Gibbs free energy of that reaction is computed by computing the equilibrium constant as:
[tex]K=\frac{p_{NOCl}^2}{p_{NO}^2p_{Cl_2}} =\frac{8.64^2}{9.47^2*2.61}=0.319[/tex]
Hence the Gibbs free energy:
[tex]\Delta _rG=-RTlog(K)=-8.314\frac{J}{mol*K}*298.15K*ln(0.319)\\\\\Delta _rG=2832.2J/mol[/tex]
Best regards.