Question

Luis is standing on a street in New York City
looking at the top of the Empire State Building
with a 30° angle of elevation. He is 767.6
meters from the Empire State Building. How tall
is the Empire State Building?

Answer 1

Answer:

cos 30° =767.6/hypotenus

(make h the subject of the formular)

h = 767.6/cos 30°

h =767.6/0.154

h =4,985

approximately 5,000

Answer 2

The correct answer is 443.7

What is angle of Elevation?

• The angle of elevation is the angle formed between the line of sight and horizontal line

How to solve the problem?

• We need to find the height of the empire state building
• The angle of elevation given is 30°
• The height of the Luis given is 767.6 m
• Let us assume the height of the building is x

 According the Tangent theorem

tan30°= x / 767.6

$\frac{1}{\sqrt[]{3} }$ = x/ 767.6

Therefore , 767.6/ 1.73 = x

Therefore, x = 443.7

Hence the height of the empire state building is 443.7m

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