Question

For the reaction Fe2O3(s) + 3H2(g)2Fe(s) + 3H2O(g) H° = 98.8 kJ and S° = 143 J/K G° for this reaction would be negative at temperatures (above, below) K. Enter above or below in the first box and enter the temperature in the second box. Assume that H° and S° are constant.

Answer 1

Answer:

G° would be negative when temperatures are above 691K

Explanation:

G° could be found as:

G° = H° - TS°

As H° = 98.8 kJ and S° = 143 J/K; G° would be negative when H° < TS°, that is:

H° < TS°

98800J < 143 J/K ₓ T

691K < T

That means G° would be negative when temperatures are above 691K

I hope it helps!