Question

Mendel kept careful numerical data describing the results of his pea experiments. He knew that if alleles segregated randomly when forming gametes, mathematical probability should predict the outcome of the F2 generation. His true-breeding parent plants were homozygous, RR or rr. This cross resulted in an F1 generation of heterozygous plants, Rr. 1. What phenotypes would you predict in the F2 generation?

Answer 1

Answer:

F2 = RR, Rr, Rr rr

RR, Rr show dominant character, while rr show recessive character, because R is dominant on r.

Explanation:

As given;

Parents are RR and rr,

All F1 progeny are Rr, They all  are heterozygous.

R is dominant on r, So R show his character  in heterozygous condition.

F2 generation are;

F1 are Rr and Rr, for F2, they are parents here

so gamets are R,r,R,r

F2 = RR,Rr, Rr rr

RR, Rr show dominant character, while rr show recessive character.

Answer 2

Mendel was the father of genetics, who gave three laws on the inheritance, segregation, and assortment of the alleles.

The true-breeding parents in the Mendel experiment were purebred, such that for round seeds, they purebred RR, and wrinkled seeds, they were purebred recessive rr.

The cross between the RR and rr resulted in the F1 progeny, with round seeds and the genotype of Rr (heterozygous). The self-cross in the F1 progeny will result in 75% round seeds and 25% wrinkled seeds.

Find the attachment below for the cross between F1 progeny.

Thus, the phenotypes of the cross are RR, Rr, Rr, and rr.

To know more about the Mendelian cross, refer to the following link:

https://brainly.com/question/25301436