Show that the € operator is associative. That is, using the definition of the € operator and the rules of Boolean Algebra, show that the following equality holds:((g1,p1) € (g2,p2)) € (g3,p3) = (g1,p1) € ((g2,p2) € (g3,p3))

Respuesta :

Answer:

Explanation:

(g1,p1) € (g2,p2) € (g3,p3) = (g1,p1) € (g2,p2) € (g3,p3)

                                          = (g1,p2) € (g2,p3) € (g3,p1)

                                          = (g1,p3) € (g2,p1) € (g3,p2)

ACCESS MORE