Answer:
Electric potential energy, [tex]\Delta V=-3.32\times 10^{-11}\ volts[/tex]
Explanation:
The difference in electric potential between a thunder cloud and the ground is, [tex]V=2.08\times 10^8\ V[/tex]
We need to find the the change in electric potential energy of one of the electrons that move to the cloud. The electric potential energy is given by :
[tex]\Delta V=q\times V\\\\\Delta V=-1.6\times 10^{-19}\times 2.08\times 10^8\\\\\Delta V=-3.32\times 10^{-11}\ volts[/tex]
So, the change in electric potential energy of one of the electrons that move to the cloud [tex]-3.32\times 10^{-11}\ volts[/tex].