Question

A box of mass 12 kg is at rest on a horizontal frictionless surface. A constant horizontal force F then acts on the box and accelerates it to the right. It is observed that it takes the box 6.8 seconds to travel 30 meters. What is the magnitude of the force

Answer 1

Answer:

The magnitude of force is 15.48 N.

Explanation:

Given that,

Mass of the box, m = 12 kg

It is observed that it takes the box 6.8 seconds to travel 30 meters. We need ti find the magnitude of force. For this we must know the acceleration of the box. It is given by :

$d=ut+\dfrac{1}{2}at^2$

Here, u = 0

$d=\dfrac{1}{2}at^2\\\\a=\dfrac{2d}{t^2}\\\\a=\dfrac{2\times 30\ m}{(6.8)^2}\\\\a=1.29\ m/s^2$

The magnitude of force is given by :

$F=ma\\\\F=12\ kg\times 1.29\ m/s^2\\\\F=15.48\ N$

So, the magnitude of force is 15.48 N. Hence, this is the required solution.