Answer: Option (c) is the correct answer.
Explanation:
In an electrochemical cell, the potential difference present within the two half cells is known as cell potential.
Formula for cell potential according to Nernst equation is as follows.
[tex]E^{o}_{cell} = E^{o} - \frac{2.303RT}{nF} log (\frac{\text{Anodic ion conc.}}{\text{Cathodic ion conc.}})[/tex]
Therefore, when an increase in the cell potential (i.e., more positive E cell ) at the cathode takes place then there occurs an overall increase in the cell potential.
Also, when [tex]\frac{K}{Q} > 1[/tex] then also an increase in temperature will lead to increase in the cell potential.
Thus, we can conclude that out of the given options an increase in temperature when [tex]\frac{K}{Q}[/tex] > 1, would result in an increase in the cell potential (i.e., more positive E cell).