Answer:
The ball has a kinetic energy of 140.39 Joules
Explanation:
The kinetic energy is defined as:
[tex]KE = \frac{1}{2}mv^{2}[/tex] (1)
Where m is the mass and v is the velocity
For this particular case, the speed of the ball is 44.25m/s and its mass is 0.1434Kg.
Therefore, equation 1 can be used:
[tex]KE = \frac{1}{2}(0.1434Kg)(44.25m/s)^{2}[/tex]
But [tex]1J = Kg.m^{2}/s^{2}[/tex]
[tex]KE = 140.39J[/tex]
Hence, the ball has a kinetic energy of 140.39 Joules.