Question

The elementary reversible reaction:

2A <----> B

is carried out isothermally and isobarically in a flow reactor where pure A is fed at a concentration of 4.0 mol/dm3. If the equilibrium conversion is found to be 60%. What is the equilibrium constant, Kc if the reaction is a gas phase reaction?

Answer 1

Answer:

$Kc=0.9375$

Explanation:

Hello,

In this case, considering that A's initial concentration is 4.0mol/dm³, considering the equilibrium conversion, one obtains for the equilibrium:

$C_A^{eq}=4.0mol/dm^3*(1-x_{eq})=4.0mol/dm^3*(1-0.6)=1.6mol/dm^3\\C_B^{eq}=4.0mol/dm^3*x_{eq}=2.4mol/dm^3$

Thus, the equilibrium constant turns out:

$Kc=\frac{C_B}{C_A^2} =\frac{2.4}{1.6^2}=0.9375$

Best regards.